16t^2+30t=4

Solution for 16t^2+30t=4 equation:

16t^2+30t=4

We move all terms to the left:

16t^2+30t-(4)=0

a = 16; b = 30; c = -4;
Δ = b2-4ac
Δ = 302-4·16·(-4)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-34}{2*16}=\frac{-64}{32}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+34}{2*16}=\frac{4}{32}
=1/8
$